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If 4sin^(-1)x+6cos^(-1)x=3pi then x= . ....

If `4sin^(-1)x+6cos^(-1)x=3pi` then x= . . .

A

`(1)/(sqrt(2))`

B

`(1)/(2)`

C

0

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
We have, `4 "sin"^(-1) x + 6 cos^(-1) x = 3 pi`
`implies 4 "sin"^(-1) x + 6 ((pi)/(2) - "sin"^(-1) x) = 3 pi`
`implies 4 "sin"^(-1) x + 3 pi - 6 "sin"^(-1) x = 3pi`
`implies - 2 "sin"^(-1) x = 0 implies "sin"^(-1) x = 0`
`implies x = "sin"(0) = 0`
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