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The solution of the differential equatio...

The solution of the differential equationn `(d theta)/(dt)=-k(theta-theta_(0))` where k is constant, is . . . .

A

`theta = theta_(0) + ae^(-kt)`

B

`theta = theta_(0) + ar^(kt)`

C

`theta = 2theta_(0) - ae^(kt)`

D

`theta = 2theta_(0) - ae^(-kt)`

Text Solution

Verified by Experts

The correct Answer is:
A

We have differential equation
`(d theta)/(dt) = - k (theta - theta_(0))`, we where k is constant
`implies (d theta)/(dt) + k theta = k theta_(0)`
Which is linear differential equation in the form of
`(dy)/(dx) + Py = Q`
`:. IF = e^(int kdt) = e^(kt)`
Therefore required solution,
`(theta) (e^(kt)) = int (e^(kt) xx k theta_(0)) dt`
`implies theta e^(kt) theta_(0) + a`
`implies theta = theta_(0) + ae^(kt)`
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