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The remainder left out when 8^(2n)""(62)...

The remainder left out when `8^(2n)""(62)^(2n+1)` is divided by 9 is (1) 0 (2) 2 (3) 7 (4) 8

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To find the remainder when \( 8^{2n} - 62^{2n+1} \) is divided by 9, we can follow these steps: ### Step 1: Rewrite the expression We start with the expression \( 8^{2n} - 62^{2n+1} \). ### Step 2: Simplify \( 8^{2n} \) We can express \( 8^{2n} \) as: \[ ...
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