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int2sinxcosxdx is equal to...

`int2sinxcosxdx` is equal to

A

`cos2x+c`

B

`sin2x+c`

C

`cos^2x+c`

D

`sin^2x+c`

Text Solution

Verified by Experts

The correct Answer is:
D
`I=int2sinx.cosxdx=intsin2xdx`
`=-(cos2x)/(2)+c=-((1-2sin^(2)x))/(2)+c`
`=-(1)/(2)+sin^(2)x+c=sin^(2)x+c`
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