value of int0^((pi)/(2))cos3tdt is...

value of `int_0^((pi)/(2))cos3tdt ` is

A

`(2)/(3)`

B

`-(1)/(3)`

C

`-(2)/(3)`

D

`(1)/(3)`

Verified by Experts

The correct Answer is:

B

`int_(0)^((pi)/(2))cos3tdt=[(sin3t)/(3)]_(0)^((pi)/(2))`
`=(1)/(3)[-1-0]=(-1)/(3)`

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