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If a=(3t^2+2t+1) m/s^2 is the expression...

If `a=(3t^2+2t+1)` `m/s^2` is the expression according to which the acceleration of a particle varies. Then-
`a=(3t^2+2t+1)` `(m)/(s^2)`
Q. The change in velocity after 3 seconds of its start is:

A

30 m/s

B

39 m/s

C

3 m/s

D

20 m/s

Text Solution

Verified by Experts

The correct Answer is:
B
`V(t-0)=0`
`V_(t=3)=(3)^(3)+^(3)^(2)+3`
`=27+9+3`
`=39`
`triangleV=39-0=39(m)/(s^(2))`
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