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The sum of two forces at a point is 16N....

The sum of two forces at a point is 16N. if their resultant is normal to the smaller force and has a magnitude of 8N, then two forces are

A

6 N and 10N

B

8 N and 8 N

C

4 N and 12 N

D

2 N and 14 N

Text Solution

Verified by Experts

The correct Answer is:
A
`A+B=16` (given) …..(i)
`tanalpha=(Bsintheta)/(A+Bcostheta)=tan90^@`
`A+Bcostheta=0implies=(-A)/(B)` ..(ii)
`8=sqrt(A^(2)+B^(2)+2ABcostheta)` ..(iii)
By solving eq. (i), (ii), and (iii), we get `A=6N,B=10N`
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