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The resultant vec(P) and vec(Q) is perpe...

The resultant `vec(P) and vec(Q)` is perpendicular to `vec(P)`. What is the angle between `vec(P) and vec(Q)`?

A

`cos^(-1)((P)/(Q))`

B

`cos^(-1)((-P)/(Q))`

C

`sin^(-1)((P)/(Q))`

D

`sin^(-1)((-P)/(Q))`

Text Solution

Verified by Experts

The correct Answer is:
B

`impliestan90^@=(Qsintheta)/(P+Qcostheta)impliesP+Qcostheta=0`
`costheta=(-P)/(Q)becausetheta=cos^(-1)((-P)/(Q))`
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