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Two forces 3 N and 2 N are at an angle t...

Two forces `3 N` and `2 N` are at an angle `theta` such that the resultant is `R`. The first force is now increased of `6 N` and the resultant become `2 R`. The value of `theta` is

A

`30^@`

B

`60^@`

C

`90^@`

D

`120^@`

Text Solution

Verified by Experts

The correct Answer is:
D
`A=3N,B=2N` then `R=sqrt(A^(2)+B^(2)+2ABcostheta)`
`R=sqrt(9+4+12costheta)`
Now `A=6N,B=2N` then …(i)
`2Rsqrt(36+4+24costheta)` .(ii)
from (i) and (ii) we get `costheta=-(1)/(2)becausetheta=120^@`
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