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vecA=2hati+hatj,B=3hatj-hatk and vecC=6h...

`vecA=2hati+hatj`,`B=3hatj-hatk` and `vecC=6hati-2hatk`.
value of `vecA-2vecB+3vecC` would be

A

20hati+5hatj+4hatk`

B

`20hati-5hatj-4hatk`

C

`4hati+5hatj+20hatk`

D

`5hati+4hatj+10hatk`

Text Solution

Verified by Experts

The correct Answer is:
B
`vecA-2vecB+3vecC=(2hati+hatj)-2(3hatj-hatk)+3(6hati-2hatk)`
`2hati+hatj-2hatk+18hati-6hatk=20hati-5hatj-4hatk`
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