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The position vector of a particle is det...

The position vector of a particle is determined by the expression `vec r = 3t^2 hat i+ 4t^2 hat j + 7 hat k`. The displacement traversed in first `10` seconds is :

A

500m

B

300m

C

150m

D

100m

Text Solution

Verified by Experts

The correct Answer is:
A
`vecr=3t^(2)hati+4t^(2)hatj+7hatk`
at `t=0,vecr_1=7hatk`
at `t=10sec,vecr_2=300hati+400hatj+7hatk`
`vec(triangler)=vecr_2-vecr_1=300hati+400hatj`
`|vec(triangler)|=|vecr_2-vecr_1|=sqrt((300)^(2)+(400)^(2))=500m`
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