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The position of a particle moving in the...

The position of a particle moving in the xy plane at any time t is given by `x=(3t^2-6t)` metres, `y=(t^2-2t)` metres. Select the correct statement about the moving particle from the following

A

The acceleration of particle is zero at `t=0` second

B

the velocity of the particle is zero `t=0` second

C

the velocity of the particle is zero at `t=1` second

D

the velocity and acceleration of the particle are never zero

Text Solution

Verified by Experts

The correct Answer is:
C
`v_x=(dx)/(dt)=(d)/(dt)(3t^2-6t)=6t-6` at `t=1`,`v_x=0`
v_y=(dy)/(dt)=(d)/(dt)(t^2-2t)=2t-2` at `t=1`,`v_y=0`
hence `v=sqrt(v_x^2+v_y^2)=0`
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