Home
Class 12
PHYSICS
The acceleration a in ms^-2 of a particl...

The acceleration a in `ms^-2` of a particle is given by `a=3t^2+2t+2`, where t is the time. If the particle starts out with a velocity `v=2ms^-1` at `t=0`, then find the velocity at the end of `2s`.

A

12 `(m)/(s)`

B

18 `(m)/(s)`

C

27 `(m)/(s)`

D

36 `(m)/(s)`

Text Solution

Verified by Experts

The correct Answer is:
B
`v=u+intadt=u+int(3t^2+2t+2)dt`
`=u+(3t^3)/(3)+(2t^2)/(2)+2t=u+t^3+t^2+2t`
`=2+8+4+4=18(m)/(s)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The acceleration a in "m/s^(2)" of a particle is given by,a=3t^(2)+2t+2 where t is the time.If the particle starts out with a velocity u=2m/s at t=0then the velocity at the end of 2 second is

The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.

[" The acceleration ' "a" ' (in "m/s^(2)" ) of a particle is "],[" given by "a=3t^(2)+2t-2" ,where "t" is time in "],[" second.If the particle starts with "10m/s" at "t=],[0" ,then the velocity at "t=2s" is "]

The acceleration a of a particle in m/s^2 is give by a=18t^2+36t+120 . If the particle starts from rest, then velocity at end of 1 s is

The velocity of a particle is given by v=12+3(t+7t^2) . What is the acceleration of the particle?

If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

If velcotiy of a particle is given by v=2t-1 then find the acceleration of particle at t = 2s.

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is

If acceleration of a particle at any time is given by a = 2t + 5 Calculate the velocity after 5 s, if it starts from rest