A particle moving along a straight line with a constant acceleration of `-4 m//s^2` passes through a point `A` on the line with a velocity of `+ 8 m//s` at some moment. Find the distance travelled by the particle in `5` seconds after that moment.

Answer

26 m

Explanation

`u=+8(m)/(s)`,`a=-4(m)/(s^2)`
`v=0`
`implies0=-4t` or `t=2` sec
Displacement in first 2 sec
`S_1=8xx2+(1)/(2).(-4).2^2=8`m
Displacement in nexy 3 sec.
`S_2=0xx3+(1)/(2)(-4)3^2=-18`m
Distance travelled `=|S_1|+|S_2|=26`m