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Two bodies are thrown simultaneously fro...

Two bodies are thrown simultaneously from a tower with same initial velocity `v_0`: one vertically upwards, the other vertically downwards. The distance between the two bodies after time t is

A

`2v_0t+(1)/(2)gt^2`

B

`2v_0t`

C

`v_0t+(1)/(2)g` `t^2`

D

`v_0t`

Text Solution

Verified by Experts

The correct Answer is:
B
For vertically upward mation, `h_1v_0t-(1)/(2)gt^2` and for vertically downward motion, `h_2=v_0t+(1)/(2)gt^2`
Total distance covered in t sec `h=h_1+h_2=2v_0t`
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