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Velocity of a stone projected, 2 second ...

Velocity of a stone projected, 2 second bofore it reaches the maximum height makes angle `53^@` with the horizontal then the velocity at highest point will be

A

`20(m)/(s)`

B

`15(m)/(s)`

C

`25(m)/(s)`

D

`(80)/(2)(m)/(s)`

Text Solution

Verified by Experts

The correct Answer is:
B

Two second before maximum height
`0=v_y-g t`
`v_y=g timpliesv_y=gxx2=20(m)/(s)`
`tan53^@=(20)/(v_x)=v_x=15(m)/(s)`
at maximum height `v=v_x=15(m)/(s)`
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