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A stone is projected from point A with s...


A stone is projected from point A with speed u making an angle `60^@` with horizontal as shown. The fixed inclined suface makes an angle `30^@` with horizontal. The stone lands at B after time t. Then the distance AB is equal to

A

`(ut)/(sqrt3)`

B

`(sqrt3)/(2)`

C

`sqrt3ut`

D

`2ut`

Text Solution

Verified by Experts

The correct Answer is:
A


The horizontal displacement in time t is `AC=ucos60^@t=(ut)/(2)`
Range on inclined plane`=(AC)/(cos30)=(ut)/(sqrt3)`
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