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A person aiming to reach the exactly opp...

A person aiming to reach the exactly opposite point on the bank of a stream is swimming with a speed of `0.5(m)/(s)` at an angle of `120^@` with the direction of flow of water. The speed of water in the stream is

A

`1(m)/(s)`

B

`0.5(m)/(s)`

C

0.25(m)/(s)`

D

`0.433(m)/(s)`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the swimmer's motion relative to the flow of the stream. The swimmer is trying to reach a point directly opposite on the bank of the stream while swimming at an angle of 120 degrees to the direction of the stream's flow. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Speed of the swimmer, \( v_s = 0.5 \, \text{m/s} \) - Angle with the direction of the stream, \( \theta = 120^\circ \) 2. **Break Down the Swimmer's Velocity:** The swimmer's velocity can be resolved into two components: - **Horizontal Component (along the stream):** \[ v_{sx} = v_s \cdot \cos(120^\circ) = 0.5 \cdot \cos(120^\circ) = 0.5 \cdot (-0.5) = -0.25 \, \text{m/s} \] - **Vertical Component (across the stream):** \[ v_{sy} = v_s \cdot \sin(120^\circ) = 0.5 \cdot \sin(120^\circ) = 0.5 \cdot \left(\frac{\sqrt{3}}{2}\right) = \frac{\sqrt{3}}{4} \, \text{m/s} \] 3. **Determine the Speed of the Stream:** To reach the point directly opposite, the horizontal component of the swimmer's velocity must cancel out the speed of the stream. Let \( u \) be the speed of the stream. Therefore, we have: \[ -0.25 \, \text{m/s} = -u \implies u = 0.25 \, \text{m/s} \] 4. **Final Result:** The speed of the water in the stream is: \[ u = 0.25 \, \text{m/s} \]

To solve the problem, we need to analyze the swimmer's motion relative to the flow of the stream. The swimmer is trying to reach a point directly opposite on the bank of the stream while swimming at an angle of 120 degrees to the direction of the stream's flow. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Speed of the swimmer, \( v_s = 0.5 \, \text{m/s} \) - Angle with the direction of the stream, \( \theta = 120^\circ \) ...
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