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A train in standing on a platform, a man...

A train in standing on a platform, a man inside a compartment of a train drops a stone. At the same instant train starts to move with constant acceleration. The path of the particle as seen by the person who drops the stone is:

A

parabola

B

straight line for some time & parabola for the remaining time

C

straight line

D

variable path that cannot be defined

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of the stone dropped by the man inside the moving train. The train starts moving with a constant acceleration at the same moment the stone is dropped. ### Step-by-Step Solution: 1. **Identify the Reference Frames**: - The man inside the train is in a non-inertial frame because the train is accelerating. - The stone is dropped from rest relative to the man. 2. **Motion of the Stone**: - When the stone is dropped, it has an initial velocity of 0 m/s in the vertical direction (downward). - The only force acting on the stone after it is dropped is gravity, which causes it to accelerate downward with an acceleration \( g \). 3. **Motion of the Train**: - The train starts moving with a constant acceleration \( a \) to the right. - As the train accelerates, the position of the man in the train changes relative to the stone. 4. **Equations of Motion**: - For the stone (in the vertical direction): \[ y = \frac{1}{2} g t^2 \] - For the train (in the horizontal direction): \[ x = \frac{1}{2} a t^2 \] 5. **Eliminate Time (t)**: - From the equation of motion for the train, we can express time \( t \) in terms of \( x \): \[ t = \sqrt{\frac{2x}{a}} \] - Substitute this expression for \( t \) into the equation for the stone: \[ y = \frac{1}{2} g \left(\sqrt{\frac{2x}{a}}\right)^2 \] - Simplifying this gives: \[ y = \frac{1}{2} g \cdot \frac{2x}{a} = \frac{g}{a} x \] 6. **Conclusion**: - The equation \( y = \frac{g}{a} x \) represents a straight line passing through the origin. - Therefore, the path of the stone as seen by the man in the train is a straight line. ### Final Answer: The path of the particle (stone) as seen by the person who drops it is a straight line.

To solve the problem, we need to analyze the motion of the stone dropped by the man inside the moving train. The train starts moving with a constant acceleration at the same moment the stone is dropped. ### Step-by-Step Solution: 1. **Identify the Reference Frames**: - The man inside the train is in a non-inertial frame because the train is accelerating. - The stone is dropped from rest relative to the man. ...
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