Home
Class 12
PHYSICS
In the figure, at the free end of the li...


In the figure, at the free end of the light string, a force F is spplied to keep the suspended mass of 18 kg at rest. Then the force exerted by the cirling on the system (assume that the string segments are vertical and the pulleys are light and smooth) is:(`g=10(m)/(s^2)`)

A

60 N

B

120 N

C

180 N

D

240 N

Text Solution

Verified by Experts

The correct Answer is:
D



FBD of 18 kg block
`18xxgimplies=180N` {as it is at rest}
For the lower pulley:
Clearly: `3T_1=TimpliesT_1=60N`
and for the upper pulley:
`T_2=4T_1=240N`
where `T_2` is the force exerted by the celling on the pulley.
Promotional Banner

Similar Questions

Explore conceptually related problems

In the figure at the free end a force F is applied to keep the suspended mass of 18 kg at rest. The value of F is-

In the figure at the free end a force F is applied to keep the suspended mass of 8 kg at rest. The value of F is :

The system shown in fig, is released from rest. Calculate the tension in the string and the force exerted by the string on the pulleys, assuming pulleys and strings are massless.

In the following figure, the object of mass m is held at rest by a horizontal force as shown. The force exerted by the string on the block is -

In the arrangement shown in figure, what should be the mass of block A so that the system remains at rest. Also find force exerted by string on the pulley Q. (g = 10 m//s^(2))

All the surface are smooth and the strings ans pulleys are light. The force exerted by the 20 cm part of the rod on the 10 cm part is

Calculate the tension in the string shown in (a) The pulleys and the string are light and all surfaces are frictionless. (g=10m//s^(2))

A constant force F=m_2g/s is applied on the block of mass m_1 as shown in figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m_1