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A car is moving on a plane inclined at 3...

A car is moving on a plane inclined at `30^(@)` to the horizontal with an acceleration of `10m//s^(2)` parallel to the plane upward. A bob is suspended by a string from the roof. The angle in degrees which the string makes with the vertical is: (Assume that the bob does not move relative to car) `[g=10m//s^(2)]`

A

`20^@`

B

`30^@`

C

`45^@`

D

`60^@`

Text Solution

Verified by Experts

The correct Answer is:
B

If F.B.D of the bob resolving the components of pseudo force and tension in horizontal and vertical direction.
`Tsinalpha=macostheta`
`Tcosalpha=masinalpha+mg`
From (i) and (ii), `tanalpha=(asintheta)/(asintheta+g)`
Here `a10(m)/(s^2)`,`theta=30^@`
After solving we get `tanalpha=(1)/(sqrt(3))` or `alpha=30^@`
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