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A body of mass m is placed over a smooth...

A body of mass `m` is placed over a smooth inclined plane of inclination `theta`. Which iis placed over a lift which is moving up with an acceleration `a_(0)` . Base length o f the inclined plane is `L` . Calculate the velocity of the block with respect to lift at the bottom, if it is allowed to slide down from the top of the plane from rest.

A

`sqrt(2(a_0+g)Lsintheta)`

B

`sqrt(2(a_0+g)Lcostheta)`

C

`sqrt(2(a_0+g)Ltantheta)`

D

`sqrt(2(a_0+g)Lcottheta)`

Text Solution

Verified by Experts

The correct Answer is:
C
Acceleration along the plane with respect to lift is,
`a=(a_0+g)sintheta`
Initial velocity`=0`
`v^2=u^2+2as`
`v=sqrt(2(a_0+g)sintheta(L)/(costheta))`
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