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In the given arrangement, mass of the bl...


In the given arrangement, mass of the block is M and the surface on which the block is placed is smooth. Assuming all pulleys to be massless and frictionless, strings to be inelastic and light, `R_1`,`R_2` and `R_3` to be light supporting rods, then acceleration of point `P` will be (A is fixed):

A

0

B

`infty`

C

`(4F)/(m)`

D

`(2F)/(m)`

Text Solution

Verified by Experts

The correct Answer is:
C

F.B.D of the mass M:
`T=F`
`ma=2T=2Fimpliesa=(2F)/(m)`
So, acceleration of point P is `2a=(4F)/(m)` (from constraint relation)
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