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A perfectly straight protion of a unifor...

A perfectly straight protion of a uniform rope has mass `M` and length `L` . At end `A` of the segment, the tension in the rope is `T_(A)` and at end `B` it is `T_(B)(T_(B)gtT_(A)`) . Neglect effect of gravity and no contact force acts on the rope in between points `A` and `B` . The tension in the rope at a distance `L//5` from end `A` is.

A

`T_B-T_A`

B

`((T_A+T_B))/(5)`

C

`((4T_A+T_B))/(5)`

D

`((T_A-T_B))/(5)`

Text Solution

Verified by Experts

The correct Answer is:
C


The F.B.D. of section of rope between A and B having acceleration a towards left is
Applying Newton's second law on section AB and section AC of rope we get
`T_B-T_A=Ma` and `T_C-T_A=(M)/(5)a`
Solving `T_C=(T_B+4T_A)/(5)`
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