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Figure shows a 5 kg ladder hanging from ...


Figure shows a 5 kg ladder hanging from a string that is connected with a ceiling and is having a spring balance connected in between. A boy of mass 25 kg is climbing up the ladder at acceleration `1(m)/(s^2)`. Assuming the spring balance and the string to be massless and the spring to show a constant reading, the reading of thespring balance is: (Take`g=10(m)/(s^2)`)

A

30 kg

B

32.5 kg

C

35 kg

D

37.5 kg

Text Solution

Verified by Experts

The correct Answer is:
B
If reading of spring balance is T, then applying NLM on (man`+`ladder) system
`T-(25+5)g=25a`
`T-30g=25aimpliesT-300=25(1)`
`impliesT=325N=32.5kg`
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