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Block B of mass 2 kg rests on block A of...


Block B of mass 2 kg rests on block A of mass 10 kg. All surfaces are rough with the value of coefficient of friction as shown in the figure. Find the minimum force F that should ber appplied on blocks A to cause relative motion between A and B.`(g=10(m)/(s^2)`)

A

24 N

B

30 N

C

48 N

D

60 N

Text Solution

Verified by Experts

The correct Answer is:
C


`FBD of B (a_(B))(_(max)=(f_max)/(m_B)=mu_(S)g=2.5(m)/(s^2)`
FBD of combined system
`f_k=0.15(2+10)g=18N`
`F_(max)-f_k=(m_A+m_B)(a_B)_(max)`
`impliesF_(max)=f_k+12xx2.5=48N`
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