A small mass of 10 g lies in a hemispherical bowl of radius 0.5 m at a height of 0.1 m from the bottom of the bowl. The mass will be in equilibrius if the bowl rotates at an

Options

A. `(10)/(sqrt3)(rad)/(s)`
B. `10sqrt3(rad)/(s)`
C. `5(rad)/(s)`
D. none of these

Answer

C

Explanation

`Nsintheta=mromega^2`
`Nsintheta=mromega^2`
`tantheta=(romega^2)/(g)`
`omega=sqrt((g tantheta)/(r ))`
`omega=5(rad)/(s)`