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A ring of mass m can slide over a smooth...

A ring of mass m can slide over a smooth vertical rod. The ring is connected to a spring of force constant `K=(4mg)/R` where 2R is the natural length of the spring. The other end spring is fixed to the ground at a horizontal distance 2R from the base of the rod. the mass is released at a height of 1.5 R from ground.

A

`(mgR)/(2)`

B

`(3mgR)/(2)`

C

`(3mgR)/(5)`

D

`mgR`

Text Solution

Verified by Experts

The correct Answer is:
A

`AC=sqrt((2R)^2+((3)/(2)R)^2)=(5)/(2)R`
Extension in length of spring `(x)=(5)/(2)R=2R=(R )/(2)`
Work done by spring `=(1)/(2)kx^2`
`=(1)/(2)((4mg)/(R ))((R^2)/(4))=(mgR)/(2)`
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