Home
Class 12
PHYSICS
The potential energy of a body is given ...

The potential energy of a body is given by `U = A - Bx^(2)` (where x is the displacement). The magnitude of force acting on the partical is

A

constant

B

Proportional to x

C

proportional to `x^2`

D

`inversely proportional to x

Text Solution

Verified by Experts

The correct Answer is:
B
`U=A-Bx^2impliesF=-(dU)/(dx)=2BximpliesFpropx`
Promotional Banner

Similar Questions

Explore conceptually related problems

The potential energy of a body is given by U=9/x^(2)-2/x The position at which its speed can be maximum is.

The potential energy of a particle is given by formula U=100-5x + 100x^(2), where U and are .

The potential energy of a partical of mass 2 kg moving in y-z plane is given by U=(-3y+4z)J where y and z are in metre. The magnitude of force ( in newton ) on the particle is :

The potential energy of a conservative system is given by U= ay^(2) -by,where y represents the position of the particle and a as well b are constants.What is the force acting on the system?

Let gravitational potential energy U is given by U=Asqrtx/(B+x^2) , where x is distance. The dimensional formula of A/B is

The potential energy U for a force field vec (F) is such that U=- kxy where K is a constant . Then

The kinetic energy of partical moving along a circule of radius R depends upon the distance covered S and given by K = aS where a is a constant. The the force acting on the partical is

The potential energy of body of mass m given by U=px+qy+rz . The magnitude of the acceleration of the body will be