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An engine pumps up 100 kg water through ...

An engine pumps up `100 kg` water through a height of `10 m` in `5 s`. If efficiency of the engine is `60%`. What is the power of the engine? `Take g = 10 ms^(2)`.

A

3.3 KW

B

0.33 KW

C

0.033 KW

D

33 KW

Text Solution

Verified by Experts

The correct Answer is:
A
Work output of engine `=mgh=100xx10xx10=10^4`J
Efficiency `(eta)`=(out put)/(i nput)` `because` input enrgy `=(output)/(eta)`
`=(10^4)/(60)xx100=(10^5)/(6)J`
`power=(i nput en ergy)/(time)=((10^5)/(6))/(5)=(10^5)/(30)=3.3kW`
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