I.` 8/sqrtX+6/sqrtX = sqrtX`
II.` y^(2) -(14^(5//2)//Y^(1//2)) = 0`

I. 7/sqrtx + 5/sqrtx = sqrtx II. y^(2) -((12)^(5//2))/sqrty = 0

(4)/(sqrtx) + (7)/(sqrtx) = sqrtx, y^(2)-((11)^(5/2))/(sqrty) = 0

In the following questions two equations numbered I and II are given. You have to solve both the equations "I. "6/sqrtx+(16)/sqrtx=sqrtx" II. "y^5-((11xx2)^(1//2))/sqrty=0

1/sqrtx (sqrtx+1/sqrtx)^2

If sqrtx+ sqrty = sqrta then y _(2)+ (1+ y_(1)) ^(3) y =

y = x+sqrtx+1/sqrtx

If sqrtx + sqrty = sqrtx , find (d^2y)/(dx^2) at x = a

y= log(sqrtx+1/sqrtx)