[" A body is raised to a height "nR" from the "],[" surface of the earth of radius R.The ratio of "],[" acceleration due to gravity on the surface of the "],[" earth to that at the given altitude is "]

A body is taken to a height of nR from the surface of the earth . The ratio of acceleration due to gravity on the surface to that at the altitude is

A body is taken to a height of nR from the surface of the earth . The ratio of acceleration due to gravity on the surface to that at the altitude is

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

A particle is taken to a height R above the earth's surface, where R is the radius of the earth. The acceleration due to gravity there is

A body of mass m rises to a height h=R/5 from the surface of earth. If g is the acceleration due to gravity at the surface of earth, the increase in potential energy is (R = radius of earth)

At what height above the surface of the earth will the acceleration due to gravity be one-fourth of its value on the surface of the earth ?[Radius of the earth =R]

A body of mass m is raised from the surface of the earth up to a height equal to the radius R of the earth. If the acceleration due to gravity on the earth's surface is g , prove that the potential energy of the body has increased by 1/2 mgR.

The acceleration due to gravity at a height R ( radius of the earth ) from the earth' s surface is

A body of mass m rises to a height h=R//5 from the earth's surface where R is earth's radius. If g is acceleration due to gravity at the earth's surface, the increase in potential energy is