" (iin) "(3^(5)times10^(5)times25)/(5^(7)times6^(3))

(3^(-5)times10^(-5)times125)/(5^(-7)times6^(-5))

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

5^(2)times25^(3)times625=(5)^(?)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

" (f) (5^(6)times a^(7))/(5^(2)times a^(3)times(10)^(0))

Simplify. (i) (25 xx t^(-4))/(5^3 xx 10 xx t^(-8)) (t != 0) (ii) (3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))

Simplify -(2)/(3)times5(1)/(2)times2times7(5)/(6)times(9)/(11)

Simplify and express the result in power notation with positive exponent: (a) "7^(5)times7^(3)-:7^(-4), (b) 6^(11)times6^(3)times6^(-5)

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))