a circle `x^2+y^2-2ax-2y=0` cuts the axis of `x` at A and circumscribes an equilateral triangle , OA as its one sides. find the value of `a` and the vertices of equilateral triangle.

A circle x^(2)+y^(2)-2ax+2y=0 cuts the axis of x at the point A and it circumscribesan equilateral triangle with OA as one of its sides, where O is the origin.Find the value of a and theertices of the equilateral triangle.

One side of an equilateral triangle is 3x+4y=7 and its vertex is (1,2). Then the length of the side of the triangle is

One side of an equilateral triangle is 3x+4y=7 and its vertex is (1,2). Then the length of the side of the triangle is

The equation of the in-circle of an equilateral triangle is x^(2) + y^(2) + 2x - 4y - 8 = 0 , find the area of the equilateral triangle.

Base of the equilateral triangle is along the line x + y- 2 = 0 and its one vertex is (2, -1). Find area of triangle.

If an equilateral triangle is inscribed in the circle x^2 + y2 = a^2 , the length of its each side is

An equilateral triangle is inscribed in the circle x^(2)+y^(2)=a^(2) . The length of the side of the triangle is

Find the height of an equilateral triangle of side x + 2.

The equation to the base of an equilateral triangle is x+y=2and its vertex is at (2,-1) . Find the length of a side of the triangle.

The equation of the base of an equilateral triangle is x+y=2 and its vertex is (2,-1). Find the length and equations of its sides.