The electronic configuration of a dipositive ion `M^(2+)` is 2, 8, 14 and its atomic mass is 56. what is the number of neutrons in its nucleus ?

The electronic configuration of a dipositive ion M2+ is 2,8,14 and its mass number is 56. What is the number of neutrons present?

The electronic configuration of a dispositive metal ion M^(2+) is 2, 8, 14 and its ionic weight is 56 amu. The number of neutrons in its nucleus would be

The electronic configuration of a dispositive ion M^2 is 2,8,14 and its atomic mass is 56.What is the number of electrons,protons and nuetorns?

The electronic configuration of a dipositive ion M^(2+) is 2, 8, 14 and its mass number is 56. The number of netrons present is

The electronic configuration of a dipositive ion M^(2+) is 2, 8, 14 and its mass number is 56. The number of netrons present is

Electronic configuration of species M^(2+) is 1s^(2) 2s^(2) 2p^(6) 3s^(6) 3d^(6) and its atomic weight is 56. The number of neutrons in the nucleus of species M is

The electronic configuration of an ion M^(2+) is 1s^(2)2s^(2)2p^(6)3s^(2)3d^(6) and the atomic weight of M is 56. The number of neutrons in the nucleus of M^(2+) is