In the formula `barx=a+((sumf_iu_i)/(sumf_i))xx h, u_i=`

In the formula bar(x)=a+h(sumf_(i)u_(i))/(sumf_(i)) for finding the mean of grouped frequency distribution u_(i) is equal to

In the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 'S and deviation from a of

In Calculating the mean of grouped data, grouped in classes of equal width, we may use the formula bar(x)=a+(sumf_(i)d_(i))/(sumf_(i)) Where, a is the assumed mean, a must be one of the mid point of the classes. Is the last statement correct? Justify your answer.

Choose the correct answer from the given four options: In the formula x=a+(sumx_(1)d_(i))/(sumf_(i)) for finding the mean of grouped data d_(i) 's are the deviations from a of

Find bar(u) in the following cases : (i) sumf_(i)u_(i)=-5,sumf_(i)=50 (ii) sumf_(i)u_(i)=21,sumf_(i)=36

Find the mean (bar(X)) in the following cases : (i) sumf_(i)6,sumf_(i)x_(i)=21 (ii) sumf_(i)x_(i)=100,sumf_(i)=25

For a frequency distribution standard deviation is computed by applying the formula\ sigma=sqrt((sumfd^2)/(sumf)-((sumfd^)/(sumf))^2) (b) sigma=sqrt(((sumfd^2)/(sumf))-(sumfd^2^)/(sumf)) (c) sigma=sqrt((sumfd^2)/(sumf)-(sumfd^^)/(sumf)) (d) sqrt(((sumfd^)/(sumf))^2-(sumfd^2^)/(sumf))

The mean of a discrete frequency distribution x_i//f_i ; i=1,\ 2,\ ddot,\ n is given by (a) (sumf_i x_i)/(sumf_i) (b) 1/n\ sum_(i=1)^nf_i x_i (c) (sumi=1nf_i x_i)/(sumi=1n x_i) (d) (sumi=1nf_i x_i)/(sumi=1n i)

For a frequency distribution standard deviation is computed by applying the formula (a) sigma=sqrt((sumfd^2)/(sumf)-((sumfd)/(sumf))^2) (b) sigma=sqrt(((sumfd)/(sumf))^2-(sumfd^2)/(sumf)) (c) sigma=sqrt((sumfd^2)/(sumf)-(sumfd)/(sumf)) (d) sigma=sqrt(((sumfd)/(sumf))^2-(sumfd^2)/(sumf))