h(dy)/(dx)+2y=x^(2)

Which of the following differential equations has y = x as one of its particular solution? (A) (d^2y)/(dx^2)-x^2(dy)/(dx)+x y=x (B) (d^2y)/(dx^2)+x(dy)/(dx)+x y=x (C) (d^2y)/(dx^2)-x^2(dy)/(dx)+x y=0 (D) (d^2y)/(dx^2)+x(dy)/(dx)+x y=0

Solve (x+y(dy)/(dx))/(y-x(dy)/(dx))=x^(2)+2y^(2)+(y^(4))/(x^(2))

The first integral of (dy)/(dx)((d^(2)y)/(dx^(2)))-x^(2)y((dy)/(dx))=xy^(2) will be

((dy)/(dx))^(2) + 2y cot x (dy)/(dx) = y^(2) has the solution

((dy)/(dx))^(2) + 2y cot x (dy)/(dx) = y^(2) has the solution

((dy)/(dx))^(2) + 2y cot x (dy)/(dx) = y^(2) has the solution

If sqrt(1-x^6)+sqrt(1-y^6)=a(x^3-y^3),p rov et h a t(dy)/(dx)=(x^2)/(y^2)sqrt((1-y^6)/(1-x^6) where -1

If y=x log((x)/(a+bx)), thenx ^(3)(d^(2)y)/(dx^(2))= (a) x(dy)/(dx)-y (b) (x(dy)/(dx)-y)^(2)y(dy)/(dx)-x(d)(y(dy)/(dx)-x)^(2)

Solve y-x(dy)/(dx)=a(y^(2)+(dy)/(dx))