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Check whether 6^(n) can end with the dig...

Check whether `6^(n)` can end with the digit '0' (zero) for any natural number n.

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Assertion (A): 6^(n) ends with the digit zero where n is a natural number. Reason (R):Any number ends with digit zero, if its prime factor is of the form 2^(m)xx5^(n) , where m,n are natural numbers.

p^(n)=(axx5)^(n) For p^(n) to end with the digit zero a- ________________ for natural number of n.