`Tan[Tan^-1 (1/(a+b))+tan^(- 1)(b/(a^2+a b+1))]=`

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tan[tan^(-1)(1/(a+b))+tan^(-1)(b/(a^(2)+ab+1))]=

The value of tan[Tan^(-1)(1/(a+b))+Tan^(-1)(b/(a^(2)+ab+1))] is

The value of sec[tan^(-1)((b+a)/(b-a))-tan^(-1)((a)/(b))] is

if a>b>0 then the value of tan^(-1)((a)/(b))+tan^(-1)((a+b)/(a-b)) is

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tan^(-1)a+tan^(-1)b=(pi)/(2)