In a ` A B C ,` , if C is a right angle, then `tan^(-1)(a/(b+c))+tan^(-1)(b/(c+a))=` `pi/3` (b) `pi/4` (c) `(5pi)/2` (d) `pi/6`

In a triangle A B C , , if C is a right angle, then tan^(-1)(a/(b+c))+tan^(-1)(b/(c+a))= (a) pi/3 (b) pi/4 (c) (5pi)/2 (d) pi/6

In a ABC, if C is a right angle,then tan^(-1)((a)/(b+c))+tan^(-1)((b)/(c+a))=(pi)/(3)(b)(pi)/(4)( c) (5 pi)/(2)( d) (pi)/(6)

If C is a right angle in the triangle ABC, show that, tan^(-1) 'a/(b+c)' + tan^(-1) 'b/(c+a)' = pi/4 .

If in triangle ABC, C = 90^circ then prove that tan^(-1) (a/(c+b)) + tan^(-1) (b/(a+c)) = pi/4 .

sin^(-1)((-1)/2) (a) pi/3 (b) -pi/3 (c) pi/6 (d) -pi/6

If angle A = 90 ^(@) in the triangle ABC, then tan ^(-1) (( c )/(a+b)) + tan ^(-1) ((b)/(a+c)) is equal to : a)0 b)1 c) (pi)/(4) d) (pi )/(6)

tan^(-1)(x/y)-tan^(-1)((x-y)/(x+y)) is (A) pi/2 (B) pi/3 (C) pi/4 (D) pi/4 or (3pi)/4

tan^(-1)(x/y)-tan^(-1)((x-y)/(x+y)) is (A) pi/2 (B) pi/3 (C) pi/4 (D) pi/4 or (3pi)/4

tan^(-1)(x/y)-tan^(-1)((x-y)/(x+y)) is (A) pi/2 (B) pi/3 (C) pi/4 (D) pi/4 or (3pi)/4

If the equation x^3+b x^2+c x+1=0,(b (a) -pi (b) -pi/2 (c) pi/2 (d) pi