`"I f"cos^(- 1)x+cos^(- 1)y=pi/2,tan^(- 1)x-tan^(- 1)y=0` then `x^2+x y+y^2=`

If cos^(-1)x+Cos^(-1)y=(pi)/2 and Tan^(-1)x-Tan^(-1)y=0 then x^(2)+xy+y^(2)=

If sin^(-1)x+sin^(-1)y=pi//2 and cos^(-1)x-cos^(-1)y=0 , then values x and y are respectively

If x=2. y=3 , then tan^(-1)x+tan^(-1)y=

If sin^(-1) x + sin^(-1)y = pi//2 and cos^(-1) x - cos^(-1) y = 0 , then value x and y respectively

Prove that sin ^ (- 1) x + cos ^ (- 1) y = (tan ^ (- 1) (xy + sqrt ((1-x ^ (2)) (1-y ^ (2)))) ) / (y sqrt (1-x ^ (2)) - x sqrt (1-y ^ (2)))

tan (sin ^(-1)x+sin ^(-1) y) +tan (cos^(-1)x+cos ^(-1)y)

If tan ^(-1) x+tan ^(-1) y+tan ^(-1) z=(pi)/(2) then x y+y z+z x=

If tan ^(-1) x+tan ^(-1) y+tan ^(-1) z=(pi)/(2), then 1-x y-y z-z x=

If cos^(-1) x + cos^(-1) y + cos ^(-1) z = pi and 0 lt x,y,z lt 1 show that x^(2) +y^(2) +z^(2) +2xyz = 1