" 15.If "cot theta=(7)/(8)" ,then the value of "((1+sin theta)(1-sin theta))/((1+cos theta)(1-cos theta))=

If cot theta=(7)/(8) then find the value ((1-sin theta)(1+sin theta))/((1-cos theta)(1+cos theta))

If cot theta=(15)/(8), then Evaluate ((2+2sin theta)(1-sin theta))/((1+cos theta)(2-2cos theta))

Given cot theta =(7)/(8) , then evaluate (i) ((1+sin theta )( 1-sin theta ))/( (1+cos theta )(1-cos theta )) " "(ii) ((1+sin theta ))/( cos theta )

Given cot theta =(7)/(8) , then evaluate (i) ((1+sin theta )( 1-sin theta ))/( (1+cos theta )(1-cos theta )) " "(ii) ((1+sin theta ))/( cos theta )

Given cot theta =(7)/(8) , then evaluate (i) ((1+sin theta )( 1-sin theta ))/( (1+cos theta )(1-cos theta )) " "(ii) ((1+sin theta ))/( cos theta )

If quad cot theta=(7)/(8) ,evaluate: ( i ) ((1+sin theta)(1-sin theta))/((1+cos theta)(1-cos theta)) (ii)

Given cot theta =(7)/(8) , then evaluate (i) ((1+sin theta )( 1-sin theta ))/( (1+cos theta )(1-cos theta )) " "(ii) cot^2 theta

If cot theta = 7/8 , evaluate: (i) ((1+sin theta)(1-sin theta))/((1+cos theta) (1-cos theta))

If cot theta=(7)/(8), evaluate.1.)((1+sin theta)(1-sin theta))/((1-cos theta)(1+cos theta))