Home
Class 12
MATHS
Let I be the purchase value of an equipm...

Let I be the purchase value of an equipment and V(t) be the value after it has been used for t years. The value V(t) depreciates at a rate given by differential equation `(d V(t)/(dt)=-k(T-t)` , where `k"">""0` is a constant and T is the total life in years of the equipment. Then the scrap value V(T) of the equipment is : (1) `T^2-1/k` (2) `I-(k T^2)/2` (3) `I-(k(T-t)^2)/2` (4) `e^(-k T)`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    JEE MAINS PREVIOUS YEAR|Exercise All Questions|21 Videos

  • B. Arch 2021 (A)

    JEE MAINS PREVIOUS YEAR|Exercise QUESTION|13 Videos

Similar Questions

Explore conceptually related problems

V = k((P)/(T))^(0.33) where k is constant. It is an,

The temperature T(t) of a body at time t=0 is 160^(@)F and it decreases continuously as per the differential equation (dT)/(dt)=-K(T-80) ,where K is a positive constant.If T(15)=120^(@)F ,then T(45) is equal to

The velocity of a particle is given by v=v_(0) sin omegat , where v_(0) is constant and omega=2pi//T . Find the average velocity in time interval t=0 to t=T//2.

If current I = K cos omega t , (where K is a constant and t is time), then RMS value of current for one complete cycle is

The instantaneous velocity of a particle moving in a straight line is given as a function of time by: v=v_0 (1-((t)/(t_0))^(n)) where t_0 is a constant and n is a positive integer . The average velocity of the particle between t=0 and t=t_0 is (3v_0)/(4 ) .Then , the value of n is