In Figure, a quadrilateral ABCD is drawn to circumscribe a circle .
Prove that
`AB+CD=BC+AD`

A quadrilateral ABCD is drawn to circumscribe a circle.Prove that AB+CD=AD+BC

In figure, a quadrilateral ABCD is drawn to circumscribe a circle such that its sides AB, BC, CD and AD touch the circle at P, Q, R and S respectively. If AB = x cm, BC = 7 cm, CR = 3cm and AS = 5cm, then x = ______.

In Fig.2, a quadrilateral ABCD is drawn to circumscribe a circle, with centre O, in such a way that the sides AB, BC, CD and DA touch the circle at the points P, Q, R and S respectively. Prove that AB + CD = BC + DA.

If a hexagon ABCDEF circumscribe a circle, prove that AB+CD+EF=BC+DE+FA

In a hexagon ABCDEF circumscribe a circle, prove that AB+CD+EF=BC+DE+FA.

If the sides of a quadrilateral ABCD touch a circle prove that AB+CD=BC+AD.

In Figure,diagonal AC of a quadrilateral ABCD bisects the angles A and C. Prove that AB=AD and CB=CD

In the figure, diagonal AC of a quadrilateral ABCD bisects the angles A and C. Prove that AB = AD and CB = CD.