5 g of a substance when dissolved in 50 g water lowers the freeezing by `1.2^(@)C`. Calculate molecular wt. of the substance if molal depression constant of water is `1.86^(@)C` K kg `mole^(-1)`.

5 g of a substance when dissolved in 50 g water lowers the freezing by 1.2^(@)C . Calculate molecular wt. of the substance if molal depression constant of water is 1.86 K kg mol^-1 .

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

0.48g of a substance was dissolved in 10.6 g C_6H_6. The freezing point of benzene was lowered by 1.8^@C. Calculate molar mass of the substance. Molecular depression constant for benzene is "5K kg mol"^(-1) .

0.48 g of a substane was dissolved in 10.6g C_(6)H_(6) . The freezing point of benzene was lowered by 1.8^(@)C . Calculate m.w.t. of the substance. Molecular depression constant for benzene is 50 K"mol"^(-1) 100 g .