`c s c h^(- 1)(-4)=`

Evaluate each of the following: "c o s e c"^(-1)("c o s e c"pi/4) (ii) "c o s e c"^(-1)("c o s e c"(3pi)/4)

Evaluate each of the following: "c o s e c"^(-1)("c o s e c"pi/4) (ii) "c o s e c"^(-1)("c o s e c"(3pi)/4)

Evaluate: "c o s e c"{cot^(-1)(-4/3)}

Given S_(C_(2)H_(6))^(@) = 225 J mol^(-1) K^(-1) , S_(C_(2)H_(4)^(@) = 220 J mol^(-1) K^(-1), S_(H_(2)^(@) = 130 J mol^(-1) K^(-1) Then Delta S^(@) for the process C_(2)H_(4) + H_(2) rightarrow C_(2)H_(6) is

Given S_(C_(2)H_(6))^(@) = 225 J mol^(-1) K^(-1) , S_(C_(2)H_(4)^(@) = 220 J mol^(-1) K^(-1), S_(H_(2)^(@) = 130 J mol^(-1) K^(-1) Then Delta S^(@) for the process C_(2)H_(4) + H_(2) rightarrow C_(2)H_(6) is

Calculate the enthalpy for the reaction at 27^0C . C_2 H_5 Cl (s) rarr C H_4 (g) +HCl (g) , Delta H^0(C -C) = 350 kjmol ^(-1) H^0(C-H) = 410 Kjmol^(-)1 , Delta H(C = C) =600 kjmol^(-1) -Delta H^0(C-Cl) = 340^0k jmol^(-1) , Delta H^0(H-Cl) = 430 kjmol^(-1) .

In C^(1) H_(3) C^(2) -= C^(3) - C^(4) H_(2) - C^(5)H = C^(6) H_(2) , hybridisation state of carbon number 1 , 3 and 5 are respectively -

In an LC circuit shows in Fig. C = 1 F , L = 4 H . At time t = 0 , charge in the capacitor is 4 C and it is decreasing at the rate of sqrt(5) C s^(-1) . Choose the corrent statement.

In an LC circuit shows in Fig. C = 1 F , L = 4 H . At time t = 0 , charge in the capacitor is 4 C and it is decreasing at the rate of sqrt(5) C s^(-1) . Choose the corrent statement.