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At 90^(@)C, pure water has [H^(+)]=10^(-...

At `90^(@)`C, pure water has `[H^(+)]=10^(-6)` M.If 100 mL of `0.2` M HCl is added to 200 mL of `0.1` M KOH at `90^(@)`C then pH of the resulting solution will be :

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