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Let P and Q be 3xx3 matrices with P!=Q ....

Let P and Q be `3xx3` matrices with `P!=Q` . If `P^3=""Q^3a nd""P^2Q""=""Q^2P`, then determinant of `(P^2+""Q^2)` is equal to (1) 2(2) 1 (3)0 (4) 1

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To solve the problem, we need to find the determinant of the matrix \( P^2 + Q^2 \) given the conditions \( P^3 = Q^3 \) and \( P^2 Q = Q^2 P \). ### Step-by-Step Solution: 1. **Given Conditions**: We start with the conditions: - \( P^3 = Q^3 \) (1) - \( P^2 Q = Q^2 P \) (2) ...
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