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(sec A)/(cA)=(s)/(1-)...

(sec A)/(cA)=(s)/(1-)

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If a,b,c are in A.P. prove that: (i) (ab)^(-1),(ca)^(-1) and (bc)^(-1) are also in A.P. (ii) (ab+ac)/(bc),(bc+ca)/(ca),(ca+cb)/(ab) are also in A.P.

Suppose S_(a)(x)=sec^(-1)((x)/(a))+sec^(-1)(a) for a!=0 .If S_(a)(x)=S_(b)(x) for a!=b then x=