A body moves along a circular path of radius `5m`. The coefficient of friction between the surface of the path and the body is `0.5`. The angular velocity in `rad//s` with which the body should move so that it does not leave the path is `(g-10m//s^(-2))`

Options

A. 4
B. 3
C. 2
D. 1

Answer

D

Explanation

`mu = tan theta theta = 0.5 `
For a circular path ,
` tan theta = (u^(2))/( rg ) or 0.5 =(u^(2))/( 5xx10)`
` therefore u = 5m s^(-1)`
`u= r omega or omega = (u) /(r ) =(5)/(5) = 1 rad//"sec"`